Question

The points with the coordinates(2a,3a),(3b,2b) and (c,c) are collinear

Answer 1

solution:

if the area of triangle is 0 then there will be no triangle,the points will be col linear(on a line). let's assume that

$0=\frac{1}{2}\begin{vmatrix}2a &3a \\ 3b &2b \\c&c \\2a&2a\end{vmatrix}$

=$=4ab+3bc-2ac-9ab-2bc-2ac\\=4ab-3bc-2bc-9ab\\=4ab-9ab+bc\\=-5ab+bc\\5ab=bc\\5a=c$

this is a expiation of this question is $c=5a$

Answer 2

Answer:

for points are linear their triangle equation must be zero.

by solving this equation

5a=c

which does not show any meaning.