the poles of f(z) =z^2+1/1-z^2 is
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On 0 < |z| < 1: f(z) = −. 1 z. ·. 1. 1 − z. = −. 1 z. (1 + z + z2 +) Therefore the pole at z = 0 is simple and Res(f,0) = −1. On 1 < |z| ...
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