Question

The polynomial ax^3 + 3x^2 -3 and 2x^3-5x+a when
divided by (x +4) (x - 4) Leave the remainders R1,
and R2 respectively. If 2R ,-R2=0 find the value of a.
​

Answer 1

Step-by-step explanation:

a(x) ^3 +4(x)^2+3x-4

Now x=3 , put the value of x which is 3

f(3) = a(3) ^3 +4(3) ^2+3(3) -4... (i)

27a+36+9-4

27a+41=0....(ii)

(x) ^3-4(x)+a

3^3-4(3) +a

27-12+a

15+a=0....(iii)

As the remainder is same , we equate the eqs(ii) &(iii)

27a+41=15+a

26a=-26

a=-1

-1 is the answer... If iam not worng...

Hope the answer help you...