The polynomial. ax^3-3x^2+4 and 2x^3-5x+a.When divided by (x-2).leave the remainder p and q respectively if P=2 q=4 find a
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Using remainder theorem
x = 2
p ( 2 ) should be remainder
But p ( 2 ) is given as 2
So
P ( 2 ) = ax^3 - 3x^2 + 4
》2 = a ( 2 )^3 - 3( 2 )^2 + 4
》2 = 8a - 12 + 4
》2 = 8a - 8
》2 + 8 = 8a
》8a = 10
》a = 10/8
》a = 5/4
Hope it helps you ..!!
✌
Using remainder theorem
x = 2
p ( 2 ) should be remainder
But p ( 2 ) is given as 2
So
P ( 2 ) = ax^3 - 3x^2 + 4
》2 = a ( 2 )^3 - 3( 2 )^2 + 4
》2 = 8a - 12 + 4
》2 = 8a - 8
》2 + 8 = 8a
》8a = 10
》a = 10/8
》a = 5/4
Hope it helps you ..!!
✌
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