The polynomial ax3+3x2-13 and 2x3-5x+a are devided by x-2. The remainder in both the cases are same. Find the value of (a).
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Let P1(x)= ax³+2x²-13 and
P2(x)=2x³-5x+a
P1(-2)=P2(-2)
a(-2)³+3(-2)²-13=2(-2)³-5(-2)+a
-8a+12-13=-16+10+a
-9a-1=-6
-9a=-5
a=5/9
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