Question

the polynomial having zeroes 2,1,1 is​

Answer 1

The polynomial is x³ - 4x² + 5x - 2.

Step-by-step explanation:

Let the variable of the polynomial be x.

The zeroes of the polynomial are, 2, 1 and 1.

So, the factors of the polynomial are:

(x - 2) and (x - 1)²

Compute the polynomial as follows:

$(x-2)(x-1)^{2}=(x-2)(x^{2}-2x+1)$

                        $=x(x^{2}-2x+1)-2(x^{2}-2x+1)\\=x^{3}-2x^{2}+x-2x^{2}+4x-2\\=x^{3}-4x^{2}+5x-2$

Thus, the polynomial is x³ - 4x² + 5x - 2.

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