The polynomial P(x)=kx3+9x2+4x-8 when divided by x+3 leaves a remainder -20. find k
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well it isn't big deal
above polynomial can be written as
p(x)= (x+3)(kx² + (9-3k)x - 23 + 9k) + 61-27k
now remainder equals = 20
so 61-27k= -20 ⇒ 81 = 27k and hence k = 3
hope u get it
just used normal division method
above polynomial can be written as
p(x)= (x+3)(kx² + (9-3k)x - 23 + 9k) + 61-27k
now remainder equals = 20
so 61-27k= -20 ⇒ 81 = 27k and hence k = 3
hope u get it
just used normal division method
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