The polynomial and whaen divided by leave the same remainder in each case. Find the value of
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Dividing ax^3+3x^2-3 by x-4, we get the remainder as 45 + 64 a
Dividing 2x^3-5x+a by x-4, we get the remainder as a+108
Now, acc to question, a + 108 = 45 + 64 a
63 a = 63
a = 1
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