The polynomials (2x³+x²-ax+2) and(2x³-3x²-3x+a) when divided by x-2 leaves the same remainder. Find a.
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put x=2 in both polynomials and equalize them ,
2(2)³+2²-a(2)+2=2(2)³-3(2)²-3(2)+a
16+4-2a+2=16-36-6+a
22-2a=-26+a
22+26=a+2a
3a=48
a=48/3=16
2(2)³+2²-a(2)+2=2(2)³-3(2)²-3(2)+a
16+4-2a+2=16-36-6+a
22-2a=-26+a
22+26=a+2a
3a=48
a=48/3=16
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1
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