Math, asked by ankit358, 1 year ago

the polynomials ax cube+bx square+x-6hasx+2 asits factor and leaves a reminder 4 when divided by (x-2) find the value of a and b

Answers

Answered by Thatsomeone
2
using factor theorem

x=-2

ax^3+bx^2+x-6=0

a (-2)^3+b (-2)^2+(-2)-6=0

-8a+4b=8

-2a+b=2

using remainder theorem

x=2

a (2)^3+b (2)^2+(2)-6=4

8a+4b=8

2a+b=2

2b=4

b=2

a=0

ankit358: very nice and very well
Thatsomeone: thanks
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