the polynomials ax cube+bx square+x-6hasx+2 asits factor and leaves a reminder 4 when divided by (x-2) find the value of a and b
Answers
Answered by
2
using factor theorem
x=-2
ax^3+bx^2+x-6=0
a (-2)^3+b (-2)^2+(-2)-6=0
-8a+4b=8
-2a+b=2
using remainder theorem
x=2
a (2)^3+b (2)^2+(2)-6=4
8a+4b=8
2a+b=2
2b=4
b=2
a=0
x=-2
ax^3+bx^2+x-6=0
a (-2)^3+b (-2)^2+(-2)-6=0
-8a+4b=8
-2a+b=2
using remainder theorem
x=2
a (2)^3+b (2)^2+(2)-6=4
8a+4b=8
2a+b=2
2b=4
b=2
a=0
ankit358:
very nice and very well
Similar questions