The polynomials ax²+3x²-3 and 2x³-5x+a when divided by (x-4) leave the remainder r1 and r2 respectively If 2r1 = r2 then find a
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2
Step-by-step explanation:
Correct option is
B
127
18
By Remainder Theorem,
R
1
=a(4)
3
+3(4)
2
−3=64a+45 ...(i)
R
2
=2(4)
3
−5(4)+a=128−20+a=108+a ...(ii)
Given: 2R
1
−R
2
=0
∴2(64a+45)−(108+a)=0 (from (i) and (ii))
⇒128a+90−108−a=0
⇒127a=18
a=
127
18
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