Question

The polynomials ax²+3x²-3 and 2x³-5x+a when divided by (x-4) leave the remainder r1 and r2 respectively If 2r1 = r2 then find a​

Answer 1

Step-by-step explanation:

Correct option is

B

127

18

By Remainder Theorem,

R

1

=a(4)

3

+3(4)

2

−3=64a+45 ...(i)

R

2

=2(4)

3

−5(4)+a=128−20+a=108+a ...(ii)

Given: 2R

1

−R

2

=0

∴2(64a+45)−(108+a)=0 (from (i) and (ii))

⇒128a+90−108−a=0

⇒127a=18

a=

127

18