the polynomials f(x)=ax^3+9x^2+4x-8 when divided by (x+3) leaves (-20) as remainder. find the value of a.
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Answer:
given that f (x)=ax^3+9x^2+4x-8.
f (-3)=a. (-3)^3+9. (-3)^2+4.-3-8.
= -27a+81-12-8.
=-27a+61.
27a=61
a=61/27.
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