The polynomials kx³ + 3x² – 8 and 3x³– 5x + k are divided by x + 2. If the remainder in each case is the same, find the value of k.
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the above equation is in standard form. now consider p1(X)= kX2 + 3X2 - 8 and P2(x) = 3x3 - 0x2 -5x+k ( now it is in standard form). consider G(x) = x + 2 = 0 then it becomes x = - 2. substitute the value of x in both the equation and get the k value.
priyanka8:
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X+2=0
X= -2
P(X)= 0
P(-2)= -8K+12-8=0
-8K= -4
K=0.5
P(-2)= -24+0+10+K
-14+K=0
K=14
HOPE I HELPED YOU!!!
X= -2
P(X)= 0
P(-2)= -8K+12-8=0
-8K= -4
K=0.5
P(-2)= -24+0+10+K
-14+K=0
K=14
HOPE I HELPED YOU!!!
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