The polynomials kxcube Plus 3X square -8 and 3X cubed minus 5X plus K are divided by X +2 if the remainder in each case is the same find the value of K
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Answer:
2
Step-by-step explanation:
let, p(x) = kx³+3x²-8 & q(x) = 3x³-5x+k
given, p(x)&q(x) when divided by (x+2) gives same remainder
⇒ p(-2) = q(-2)
⇒ k(-2)³+3(-2)²-8 = 3(-2)³-5(-2)+k
⇒ -8k+12-8 = -24+10+k
⇒ 4-8k = k-14
⇒ k+8k = 4+14
⇒ 9k = 18
and hence k = 2
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