Question

The polynomtal 28-1 cuts x axes
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Answer 1

Answer:

Consider the equation y=x3−x2+2x. y=x3−x2+2x.

Whenever the graph passes through the X axis, the Y coordinate of the point of intersection would be 0. 0.

⇒ ⇒ The graph will cut the X axis whenever x3−x2+2x=0. x3−x2+2x=0.

x3−x2+2x=0⇒x(x2−x+2)=0. x3−x2+2x=0⇒x(x2−x+2)=0.

⇒x=0 ⇒x=0 or x2−x+2=0. x2−x+2=0.

The discriminant of x2−x+2=0 x2−x+2=0 is 1−8=−7<0. 1−8=−7<0.

⇒ ⇒ The equation x2−x+2=0 x2−x+2=0 does not have any real root.

⇒ ⇒ The equation x3−x2+2x=0 x3−x2+2x=0 has only one real root and it is x=0. x=0.

When x=0,y=0. x=0,y=0.

⇒ ⇒ The graph of x3−x2+2x x3−x2+2x cuts the X axis only at one point. The coordinates of this point is (0,0).

Step-by-step explanation:

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Answer 2

Answer:

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