Question

the population of a certain town was 50000 .in a year ,male population was increased by 5% and female population was increased by 3% .now the population became 52020. then what was the number of males and females in previous year?

Answer 1

Let the number of males be x and females be y
x+y = 50000
Now increased population = 2020
increased population = increased number of males + increased number of females
therefore
5% of x + 3% of y = 2020
5x/100+3y/100=2020
5x+3y = 202000
multiplying equation 1 by 3
3x+3y= 150000
solving equation 2 and 3 simultaneously
we get
2x=52000
x=26000
now put x in equation 1 we get
x+y=50000
y=50000-26000
y=24000
HOPE this helps
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