The population of a city grows at the rate of 1% per annum. If it is
10201 people at the beginning of 2015 then how much was the
population at the beginning of 2013?
Answers
Answered by
2
Answer:
Hence the population of city at the beginning of 2013
=100x=100*100=10000
Step-by-step explanation:
As shown in the figure:
let the population at the beginning of 2013 was 100x
So polation in the end of 2013 and( in the beginning of 2014)
at point B =100x+% of 100x
=100x+1*100x/100
=100x+x=101x
Now population at beginning of 2015( or at the end of 2014)
at point C=101x + 1% of 101x
=101x+1*101x/100=101x + 101x/100
As per question
101x + 101x / 100=10201
101x*100+101x = 10201*100
(10100+101)=10201*100
10201x= 10201*100
x=100
Hence the population of city at the beginning of 2013
=100x=100*100=10000
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Answered by
0
Answer: 10,000 people
Step-by-step explanation:
A=10201
R%=1
T=2015-2013=2 years
A=P(1+r/100)^2
10201=P(1+1/100)^2
10201=P(101/100)^2
10201=10201/10000P
P=10201*10000/10201
P=10,000 people
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