Question

The population of a city increase each year by 4% of what it had been at the beginning of each year.if its present population is 6760000 find (I) its population 2 years hence ,,,(ii) its population 2 years ago​

Answer 1

Step-by-step explanation:

Given :-

• The population of a city increase each year by 4%
• present population is 6760000

To Find :-

• (I) its population 2 years hence
• (ii) its population 2 years ago

Solution :-

1. The population of the city in 2 years hence

= 6760000 × (1 + 0,04)^2

= 6760000 × 1,04^2

= 7311616

2. The population of the city in 2 years ago

= 6760000 ×(1 + 0,04)^2

= 6760000 × 1,04^2

= 6250000