The population of a city increased to
64000 in 2016 at the rate of 5% pa :
(i) find the population of the city in 2014.
ii) What would be the population in 2018.
Answers
Answer:we use formula of amount of compound interest to find population
A( 2003)= 54,000,
R = 5%,
n = 2 years
In 2001 Population would be less than 2003 in two years.
A(2003)= P(2001)(1+R/100)^n
54000 = P (2001)(1+5/100)²
54000 = P(2001)(1+1/20)²
54000= P(2001)(21/20)²
54000 = P(2001)((21×21)/(20×20))
P(2001)=( 54000×20×20)/21×21
Population in 2001 = 48979.59= 48980(approx)
(ii) ATQ, population is increasing. Therefore population in 2005,
A(2005)= P(1+R/100)^n
= 54000(1+5/100)²
= 54000(1+1/20)²
= 54000( 21/20)²
= 54000(21/20)× (21/20)
=( 54000× 441)/ 400
=( 540×441)/4
= 238140/4
= 59535
Population in 2005= 59535
hope it helps u
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Step-by-step explanation:
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