Question

The population of a city increases 8% annually. If its present population is 1,42,560, then what was it a year ago?

Answer 1

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Answer 2

★$\huge\bold{\underline{\rm{\pink{Question :-}}}}$

• The population of a town increases 8% annually. If its present population is 142560, what was it a year ago ?

★$\huge\bold{\underline{\rm{\blue{Answer :-}}}}$

• It was 132000 year ago.

★$\huge\bold{\underline{\rm{\red{Given :-}}}}$

• Present population =142560

${ \pink{ \underline{According \: to \: the \: question:-}}}$

${ \small {\sf {\: Annually, \: Increase \: in \: population \: = \: 8 \%}}}$

$\\ \implies{ \red{ \tiny{\sf{ \: Present \: population = \dfrac{x(100 + increase \: in \: population)}{100} }}}}$

${ \small{ \sf{where \: x \:is \: the \: population \: last \: year,}}}$

$\therefore{ \sf{142560 = \dfrac{x(100 + 8)}{100}}} \\ \implies \: 142560 = \dfrac{108x}{100} \\ \implies \: 142560 \times 100 = 108x \\ \implies \: 14256000 = 108x \\ \implies \: x = 132000$