Question

The Population of a city increases by 10% every year . Its present population is 302500 . What was its population 2 years ago ?

Answer 1

Answer:

2,45,025

Step-by-step explanation:

Present population = 302500

10% of 302500 = $\frac{10}{100}$ * 302500 = 30250

Population of the city last year = 302500 - 30250 = 2,72,250

10% of 2,72,250 = $\frac{10}{100}$ * 272250 = 27225

Population of the city before 2 years = 272250 - 27225 = 2,45,025

So, the population of the city before 2 years was 2,45,025.

Answer 2

Given :---

• Present Population = 302500
• % increase Every year = 10%

To Find :--

• Population Before 2 years ?

Formula used :---

P = initial population,

r = rate of increasing per period,

t = number of periods,

Present Population = Before Population*(1+r/100)^t

______________________________

Solution :---

Here, P = 65000, r = 10% , t = 2 years.

Putting values we get,

→ 302500 = Before Population *( 1+10/100)²

→ 302500 = Before Population *(11/10)²

→ 302500 = Before Population * 121/100

→ Before Population = 302500 * 100 /121

→ Before Population = 250,000

Hence, Population of city Before 2 years was 250,000 ...