Question

the population of a city increases each year by 4% of what it had been at the beginning of each year.If its present population is 6760000,find:
(1)Its population 2 years hence
(2)its population 2 years ago

Answer 1

population increase=4%present population= 6760000 1. 4%of 67600004/100*6760000 =270406760000+27040=67870406787040+(4/100*6787040)=7058522(approx)(population after 2 years hence)present population= 67600004% of 6760000=270406760000-27040= 67329604% of 6732960=269318.46732960-269318.4=6463642(approx)population 2 years ago plz give thanks