The population of a city is 154250. If it increases at the rate of 10% per annum what will be population 2
years hence?
(A) 186642; 127479
(B) 156641; 127478
(C) 164789; 145894
(D) 254879; 855457
Answers
Answer:
Present population = 250000
Rate at which it is increasing = 2%
T = 2 years
After 2 year population will be
= 250000[1+
100
2
]
2
= 250000×
100
102
×
100
102
= 2,60,100
increase in population = 260100−250000=10100
Step-by-step explanation:
ese ko dekha kar value rakh lena
Concept:
The interest that is calculated using both the principal and the interest that has accrued during the previous period is called compound interest. It differs from simple interest in that the principal is not taken into account when determining the interest for the subsequent period with simple interest. Compound interest is commonly abbreviated C.I. in mathematics.
The majority of transactions in the banking and financial industries as well as other areas use compound interest. Some of its uses include:
Population growth or decline.
The expansion of bacteria
Increase or decrease in an item's value.
Amount=Principal(1+rate of interest/100)ⁿ
where, n= time
Given:
The population of a city is 154250. If it increases at the rate of 10% per annum
Find:
The population of a city is 154250. If it increases at the rate of 10% per annum what will be population 2 years hence?
Solution:
Present population =154250
Rate at which it is increasing = 10%
T = 2 years
After 2 year population will be
= 154250[1+10/100]
= 154250×110/100
= 169675
So the new population after 2 years 169675
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