Question

the population of a city is 20000. It increases at the rate of 5% per annum. Find
the population after 3 years.
Find the population of a city after 2 vears, which is at present 1200000, If the rate
of increase is 4%.
3. Amachine was bought at a price of 21.000. After one year the value of the machine
was depreciated by 5%. Find the value of the machine after one year.
4. A machinery worth 10.500 depreciated by 5%. Find its value after one year.
5. A scooter was bought at 42,000. Its value depreciated at the rate of 10% per annum.
Find its value after 2 years.

please
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Answer 1

Answer:

Step-by-step explanation:

1.

P=20000

Rate=5%

5% of 20000

5*20000/100= 1000

So the population after 3 yrs will be 1000*3 +20000= 23000

2.

P=1200000

R=4%

4% of 1200000

4*1200000/100

=48000

After 2 yrs the population would be 48k*2=96k

3.

P=21,000

5% of 21,000

5*21000/100

1050

The value was depriciated by Rs 1050

So the value of the machine after 1 ye will be 21000-1050=₹19050

4.

P=₹10,500

R=5%

5% of ₹10500

5*10500/100

₹525

The value of machine after one yr will be 10,500-525=₹9,975

5.

P=42,000

R=10%

10% of 42,000=₹4200

So the value of the scooter after two years will be 4200*2=₹8400

42,000-8400=₹35,600

Thank You

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Sincerely Sahil dhande