the population of a place increase to 54000 in 2003 at the rate of 5% per annum word per annum find the population in 2001 what would be its its population in 2005
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Answered by
2
48735 in 2001.
59535 in 2005
59535 in 2005
siddhartharao77:
the population in 2001 will be 48980
Answered by
4
Given Population in 2003 = 54000, R = 5%, n=2 years.
(1). Population in 2001 :
A = P(1+r/100)^n
54000 = P(1+5/100)^2
54000 = P(1+1/20)^2
54000 = P(21/20)^2
54000 = P * 21/20 * 21/20
P = 54000 * 20 * 20/21 * 21
= ~ 48980.
Therefore the population in 2001 = 48980.
(2). Population in 2005 :
A = P(1+r/100)^n
= 54000(1+5/100)^2
= 54000(21/20)^2
= 54000 * 21/20 * 21/20
= 59535.
Therefore the population in 2005 = 59535.
Hope this helps!
(1). Population in 2001 :
A = P(1+r/100)^n
54000 = P(1+5/100)^2
54000 = P(1+1/20)^2
54000 = P(21/20)^2
54000 = P * 21/20 * 21/20
P = 54000 * 20 * 20/21 * 21
= ~ 48980.
Therefore the population in 2001 = 48980.
(2). Population in 2005 :
A = P(1+r/100)^n
= 54000(1+5/100)^2
= 54000(21/20)^2
= 54000 * 21/20 * 21/20
= 59535.
Therefore the population in 2005 = 59535.
Hope this helps!
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