The population of a place increased to 54,000 in 2003 at a rate of 5% per annum .(i) find the population in 2001.(ii) what would be its population in 2006?
Answers
Answer:
Given that population in 2003 = 54000. Population of a place increased at the rate of 5%per annum. Population in 2002 at the rate of 5%per annum = 54000 x ( 5 / 100) = 2700 = 54000 - 2700 = 51300. Population in 2001 at the rate of 5%per annum = 51300 x ( 5 / 100) = 2565.
Step-by-step explanation:
i)
New population =54,000
Time (n)=2 yrs
r=5%
Original population = ?
54000=
(1−
100
5
)
(2)
P
54000=
0.9025
P
P=48735
Population in 2001 was 48,735.
ii)
A=54000(1+
100
5
)
(2)
=54000(1.1025)=59,535
Population in 2005 will be 59,535.
Answer:
i)
New population =54,000
Time (n)=2 yrs
r=5%
Original population = ?
54000=
(1−
100
5
)
(2)
P
54000=
0.9025
P
P=48735
Population in 2001 was 48,735.
ii)
A=54000(1+
100
5
)
(2)
=54000(1.1025)=59,535
Population in 2005 will be 59,535.