Question

the population of a place increased to 54000 in 2003 at the rate of 5% per annum find the population in 2001 what would be its population in 2005

Answer 1

1

Secondary SchoolMath13 points

"Question 10 The population of a place increased to 54000 in 2003 at a rate of 5% per annum (i) find the population in 2001 (ii) what would be its population in 2005?

Class 8 Comparing Quantities Page 134"

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Ask for details FollowReport by BrainlyHelper06.09.2017

Answers



nikitasingh79

Given:

we use formula of amount of compound interest to find population 

A( 2003)= 54,000,

R = 5%, 

n = 2 years

 

In 2001 Population would be less than 2003 in two years.


A(2003)= P(2001)(1+R/100)^n


54000 = P (2001)(1+5/100)²


54000 = P(2001)(1+1/20)²


54000= P(2001)(21/20)²


54000 = P(2001)((21×21)/(20×20))


P(2001)=( 54000×20×20)/21×21


Population in 2001 = 48979.59= 48980(approx)


(ii) ATQ, population is increasing. Therefore population in 2005,

 

A(2005)= P(1+R/100)^n


= 54000(1+5/100)²


= 54000(1+1/20)²


= 54000( 21/20)²


= 54000(21/20)× (21/20)


=( 54000× 441)/ 400


=( 540×441)/4


= 238140/4


= 59535


Population in 2005= 59535

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Hope this will help you....