Math, asked by avni14918, 1 month ago

the population of a place increased to 54000 in a certain year at the rate of 5% per annum find its population to years before what would be its population after 2 years​

Answers

Answered by farhabegum042008
2

Answer:

Thus, the population in 2001 is 48980 approximately. Now, as a population in 2003 = 54000 . Then, after a 5% increment, the population in 2004 =1.05×54000=56700. Similarly, after a 5% increment, the population in 2005 =1.05×56700=59535 .

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Answered by akhileshkumar2y2
0

this is correct answer please choose me for brainliest answer

total population increased= 54000 rate= 5% time=2yrs

p×r×t/100= 5400

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