Question

the population of a place is increased to 5400 in 2020 at a rate of 5% per annum find the population in 2018​??

​

Answer 1

Explanation:

Given that population in 2003 = 54000. Population of a place increased at the rate of 5%per annum. Population in 2002 at the rate of 5%per annum = 54000 x ( 5 / 100) = 2700 = 54000 - 2700 = 51300. Population in 2001 at the rate of 5%per annum = 51300 x ( 5 / 100) = 2565.

Answer 2

Topic

Percentage

Given

The population of a place is increased to 5400 in 2020 at a rate of 5% per annum.

To Find

The population in 2018.

Solving

Let population of that place in 2018 be x.

In 2019, it would have been increased by 5% of population in 2018.

x + 5% of x

x + ( 5x / 100 ) = 105x / 100 = 21x / 20

Now, in 2020, it would have been increased by 5% of population in 2019.

( 21x / 20 ) + ( 5% of 21x / 20 )

( 21x / 20 ) + ( 105x / 2000 )

( 21x / 20 ) + ( 21x / 400 )

( 420x + 21x ) / 400

It is given that population in 2020 is 5400.

( 441x / 400 ) = 5400

441x = 5400 × 400

441x = 2160000

x = 4897.95 ≈ 4898

Answer

So, the population of the city in 2018 was approximately 4898.