Question

the population of a small locality was 4000 in 1979 and 4500 in 1981 by what percentage had the population increased​

Answer 1

Answer:

$12.5 \%$

Step-by-step explanation:

Percentage change = $\frac{final - initial}{initial} \times 100$

∴ Percentage change = $\frac{4500 - 4000}{4000} \times 100$ = $\frac{100}{8}$ = $12.5 \%$

Answer 2

Answer:

Step-by-step explanation:

4000-100

4500-?

(4500×100)÷4000

112.5

112.5-100=12.5