Question

The population of a town 2 years ago was 62500. Since some persons migrate to different cities the number of people decreases every year at the rate of 4% per annum. Find its present population .

Answer 1

Thats ur answer ....
Hope it helps

Answer 2

Answer: 57600

Step-by-step explanation:

The given problem is a exponential  decay problem.

The exponential decay function is given by :-

$y=A(1-r)^x$, where A is  the initial amount , r is the rate of change in decimal and x is the time period.

Here, the initial population =  62500

Time period x =2

Rate of decay = 4%

Then the present population=$y=62500(1-0.04)^2=62500(0.96)^2=57600$

Hence, the present population=  57600