Question

the population of a town at present is 37380 and this is 5% more than it was one year ago. what was it's population that year. ​

Answer 1

Answer:

Let the population of last year be x

then 105% of x is 37380

105x/100=37380

Therefore x=35600

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given present population =142560

Increase in population annually =8%

Present population =

100

x(100+increaseinpopulation)

where x is population last year

∴142560=

100

x(100+8)

⇒x=132000