The population of a town at present is 50,000. If during a year the number of males increases by 5% and that females by 3%, the population would grow to 52,020 in one year. Find the number of males and females in the town at present.
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Answer:
26,000 males and 24,000 females.
Step-by-step explanation:
Total population of town = 50,000
Let the number of males = x
and females be = (50,000-x)
ATQ,
5x/100 + 1,50,000-3x/100 = 2,020
5x - 3x + 1,50,000 = 2,02,000
2x = 2,02,000 - 1,50,000
x = 52,000/2
x = 26,000
Hence there were 26,000 males in that town.
No.of females = 50,000 - 26,000 = 24,000
Hence, there were 26,000 males and 24,000 females in the town.
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