the population of a town inceases every year by 10% if the present population is 1,80,000 what will be the population of the town after 2 years
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Answered by
4
Answer:
Let the population of the town after 2 years be x
Increase percent of population every year = 10%
Present population = 180000
= 10% of 180000
= 10/100 * 180000 = 10*1800 = 18000
Increase in population after 1 year = 180000+18000 = 198000
Increase in population afer 2 years = 10% of population in 1 year + population of 1 year
= 10% of 198000+198000
= 10/100 * 198000 = 10*1980 = 19800
= 198000+19800 = 217800
Therefore, the population of the town after 2 years is 2,17,800.
Step-by-step explanation:
Answered by
1
Answer:
2,17,800
Step-by-step explanation:
Let the population of the town after 2 years be x
Increase percent of population every year = 10%
Present population = 180000
= 10% of 180000
= 10/100 * 180000 = 10*1800 = 18000
Increase in population after 1 year = 180000+18000 = 198000
Increase in population afer 2 years = 10% of population in 1 year + population of 1 year
= 10% of 198000+198000
= 10/100 * 198000 = 10*1980 = 19800
= 198000+19800 = 217800
Therefore, the population of the town after 2 years is 2,17,800.
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