The population of a town increase at annual rate 8 %. If present population of town is 7,496 the find population of town before 2 years.
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Answer:
Step-by-step explanation:
Present population =7496
Here asked the population before two years. So by annual rate we can find increasing population for a year.
In here we have to find decreasing population.
let's take the population before two years= a
So first year increasing population ;
a×8/100
End of the first year, total
population= a+a×8/100
Second year increasing population ;
(a+a×8/100)×8/100
End of the second year, total population =
= ( a+a×8/100) +[(a+a×8/100)×8/100]
This population =7496
7496=a+8a/100+8a/100+64a/100
7496=(100a+8a+8a+64a)/100
7496×100=180a
a=749600/180
a=4164.444
Population before two years=4164.44
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