The population of a town increased by 10%annually .If the present population is 2200 ,find the population a year ago
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Answer:
The population 1 year ago will be 2000.
Step-by-step explanation:
Hey Mate,
Given,
Present population of town = 2200
Rate of increase in population annually = 10%
Let the population 1 year ago be x .
So,
(x + 10% of x) = 2200
(x + x/10) = 2200
11x/10 = 2200
x = 2200 × 10/11
x = 2000
So,
The population 1 year ago will be 2000.
Hope it's help you.
Thank-you
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