Question

the population of a town increased by 6% every year. if the present population is 15900. find population a year ago​

Answer 1

Answer:

14,946

Step-by-step explanation:

The increase in population p.a.= 6%

Population in present year= 15,900

Population of previous year=

• 15,900-6%
• = 15,900 - (6/100* 15900)
• = 15,900 - 954
• = 14,946

∴ Population of previous year was 14,946

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Answer 2

Answer:

If we take the population the year before as y

then

y + (6% of y) = 15900

y + 6y/100 = 15900

100y/100 + 6y/100 = 15900

100y + 6y / 100 = 15900

106y /100 = 15900

106y = 15900 x 100

106y = 1590000

y = 1590000 / 106

y = 15000

Hence the population one year before was 15000.

hope it helps:))::)