the population of a town increases 10 percent annual .If the present population is 22000,find its population a year ago
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et the age of Seema be 4x and Shruti be 5x
Eight years from now, Seema's age will be 5x and Shruti's age will be 6x
A/q,
4x + 8 + 5x + 8 = 5x + 6x
9x + 16 = 11x
16 = 11x - 9x
2x = 16
x = \dfrac{16}{2}216
x = 8 years
Present age of Seema => 4x => 4 × 8 => 32 years
Present age of Shruti => 5x => 5 × 8 => 40 years
Eight years from now, Seema's age will be 5x and Shruti's age will be 6x
A/q,
4x + 8 + 5x + 8 = 5x + 6x
9x + 16 = 11x
16 = 11x - 9x
2x = 16
x = \dfrac{16}{2}216
x = 8 years
Present age of Seema => 4x => 4 × 8 => 32 years
Present age of Shruti => 5x => 5 × 8 => 40 years
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