Question

the population of a town increases 5% annually if its present population is 84000 what will it be in 2 years time

Answer 1

5 percent annualy so ,

5 / 100 × 84000 = 4200
population after a year
= 84000 + 4200
= 88200
repeating ,
5 / 100 × 88200 = 4410

population after two years
= 88200 + 4410
= 92610

Answer 2

Answer:

The population 2 years ago is 68000

Step-by-step explanation:

The population of a town increased = 5%

Present population = 84000

Population after each increment = x * (100+ r)/100

Let the population of city 2 years before be x

x* (105/100) x (105/100) = 84000

x=74970 * (20/21) * (20/21)

X = 68000

The population 2 years ago is 68000.

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