Question

the population of a town increases at 5% p.a it was 25500 in the year 2018. find the population in the year 2020​

Answer 1

Step-by-step explanation:

It is similar to simple interest, So use that formula.

$P=25,500\\r=5\:Percent\\T=2\:years$

$\implies$ $SI=\Large\frac{PTR}{100}$

$\implies$ $\Large\frac{25,500×5×2}{100}$

$\implies$ $SI=2,550$

$\implies$ $A=P+SI$

$\implies$ $A=25,500+2,550$

$\implies$ $\boxed{A=28,050}$

By 2020, the population will be 28,050.

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Answer 2

Step-by-step explanation:

Population of town in 2018= 25500

increase in population p.a. = 5%

population of town in 2020 = ?

population of town in 2019 = 5% of population of the town in 2018 + total population in 2018

= 5% of 25500

= 5/100 × 25500

= 5 × 255

= 1275

= 25500 + 1275

= 26775

population of town in 2020 = 5% of population in 2019 + total population in 2019

= 5% of 26775

= 5/100 ×26775

= 1338

= 26775 + 1338

= 28113 .

The population of town in 2020 will be 28113