the population of a town increases at the rate of 10% per annum. if the population is 90000 in the beginning of the year 2010,what will be the population at the beginning of the year 2012?
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8
2010 pollution = 90000
2011 pollution = 90000 10%= 90000/100 ×10 = 9000 = 90000 + 9000 = 99000
2012 pollution = 99000 + 9000 = 108000
at 2012 the pollution of town is 108000
HOPE IT'S HELPFUL
MARK AS BRANISTE
2011 pollution = 90000 10%= 90000/100 ×10 = 9000 = 90000 + 9000 = 99000
2012 pollution = 99000 + 9000 = 108000
at 2012 the pollution of town is 108000
HOPE IT'S HELPFUL
MARK AS BRANISTE
Answered by
2
Thd population will be 180000
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