Question

The population of a town increases by 10.5% every year. If its present population is 795600 what was it a year ago?


Maths
pls do it as fast as possible ​

Answer 1

Let the population of town a year ago be x.

Therefore, x+(10.5%of x) = 795600

x+105x/1000 = 795600

1105x/1000 = 795600

1105x = 795600×1000

x = 795600000/1105 = 72,000

Hence, the population a year ago was 72,000 .... Hope that helps