Question

The population of a town increases by 10.5% eyery year . If its present population is 7,95,600, what was it a year ago?​

Answer 1

Answer:

Given:

Rate Of Increase = 10.5%

Current Population= 7,95,600

Step-by-step explanation:

We know that annually the population increases

by 10.5%

Therefore if we want to find the previous years population

We must

1 Find 10.5% of 7,95,600

2 Subtract the answer from 7,95,600

Working:

$\frac{105}{1000} \times 795600$

$105 \times 795.6$

$83538$

$795600 - 83538 = 712062$

Therefore the population of the previous year is

7,12,062