Question

The population of a town increases by 10% annually if its present population is 60000 what will be its population after 2 years??

Answer 1

Percentage of increase anually = 10%

=>Percentage of increase in 2 years = 10 x 2 = 20%

Present population = 60,000

Let 'x' be the population increase

%increase = Increase in quantity  x  100

  Original quantity

 

=>20% = ___x___  x 100

  60,000

 

=>x = 20 x 600 = 12,000

 

Therefore, population after 2 years = 60,000 + 12,000 = _72,000_

Answer 2

heya!! mate

your answer is - - - -

we will use formula:
Pf=Pi×(100+R/100)^t

Pf=60000×(110/100)^2

pf=72,600 will be population after 2 years