The population of a town increases by 10% annually. If the present population is 60000,what will be the population after 2 years.
Answers
Answered by
51
10 / 100 * 60000 = 6000
population increased after a year = 60000 + 6000= 66000
10 / 100* 66000 = 6600
population after 2 years = 66000+ 6600= 72600
population increased after a year = 60000 + 6000= 66000
10 / 100* 66000 = 6600
population after 2 years = 66000+ 6600= 72600
Answered by
26
Answer :
10% of 60000 =10/100 ×60000 = 6000
population increment after a year = 60000 + 6000 = 66010 % of 66000 =10/100×66000=6600
population after 2 years=66000 + 6600= 72600
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