Question

the population of a town increases by 10% evvery year . If it is 16093 now. Its population 2 years ago was?

Answer 1

A = p(1+r/100)-n years
16093(1+10/100)-2 years
16093(11/10)-2 years
16093(10/11)
16093×10×10÷11×11
=133×10×10=
13300.

Answer 2

It is given that population of a town increases by 10% every year R = 10%.

If it is 16093 now.P = 16093.

Therefore the population 2 years ago A = 16093/(1 + 10/100)^2

                                                                    = 16093/(11/10)^2

                                                                    = 16093/(121/100)

                                                                    = 1609300/121

                                                                    = 13300.


Hope this helps!