the population of a town increases by 10 % manually if the present population is 22000 find its population a year ago
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let last year the population was = X
this year the population should be = X+ 10% of x
X + 10%of X = 22000
X + 10x / 100 = 22000
110x/100 = 22000
X = 22000*100/110 = 20000
this year the population should be = X+ 10% of x
X + 10%of X = 22000
X + 10x / 100 = 22000
110x/100 = 22000
X = 22000*100/110 = 20000
aditya2314:
Oo nice
Answered by
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Let the population is x
Given : increase by 10%
According to given question -
x + 10/100 = 22000
100x +10x /100 =22000
110x /100 =22000
110x = 22.00,000
x = 22,00,000/110
x = 20,000
Check :
20,000 x 10/100 = 2000
20,000 + 2000 =22,000
Hence : The population a year ago was 20,000
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