Question

The population of a town increases by 4% Every year. Its present population is 2,70,400. What was it 2 years ago.

Answer 1

a=p (1-r/100) whole power n is the formula

p=2,70,400

t=2 years

A=2,70,400 (1-4/100) WHOLE POWER 2

I F WE CANCEL

WE GET 249200

THEREFORE WE CAN SAY THAT THE POPULATION BEFORE 2 YEARS WAS 249200

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Answer 2

HELLO FRIEND HERE IS YOUR ANSWER,,,,,,,,,

By applying the formula of compound interest we can make the following assumptions and calculate them for the same. You'll come across this formulae.........

Let us take it as "x" years and Total population to find be "Y" and let "PP" be as present population , we'll get this ,,,

$\boxed{\bf{Y_x = PP \times [1 - \frac{r}{100}]^x}}$

Now, for population changes before "1" years ago, substitute this into "x" years ,,,

$\bf{Y_2 = 270400 \times [1 - \frac{4}{100}]^2}$

$\bf{Y_2 = 270400 \times [1 - 0.04]^2}$

$\bf{Y_2 = 270400 \times [0.96]^2}$

$\bf{Y_2 = 270400 \times [0.9216]}$

$\boxed{\bf{\therefore \: \: Y_2 = 249200.64}}$

Therefore the answer is ,,,

$\boxed{Y_2 = 2,49,200}$

HOPE THIS HELPS YOU AND CLEARS THE DOUBTS FOR CALCULATING THE TIMES OF YEAR BY THIS FORMULAE!!!!!!!