Question

the population of a town increases by 8% annually. if the present population is 14985, what was it a year ago​

Answer 1

Given,

The population of a town increases by 8% annually.

The present population is 14985.

To find out,

What was the population a year ago?

Solution:

Let the last year population be 'x'.

The present year population is 14985.

The increased percent annually is 8%.

Present population of the town = last year population of the town × (100+Increased percentage)/100

$14985 = x \times \frac{100 + 8}{100}$

$14985 = x \times \frac{108}{100}$

$x = 14985 \times \frac{100}{108}$

$x = 138.75 \times 100$

$x = 13875$

Therefore the last year population is 13875.

Verification:

$14985 = 13875 \times \frac{100 + 8}{100}$

$14985 = 13875 \times \frac{108}{100}$

$14985 = 138.75 \times 108$

$14985 = 14985$