Question

The population of a town increases by 8% annually. If the present population is 54000, what was it a year ago?​

Answer 1

Let the last year population =x 

Present year population =x+8/100

Present population =54000

So,108x/100=54000

x=54000×100/108=50,000

Hope this helps!:)

Answer 2

||GIVEN||

• Percentage of population Increased annually = 8%
• Population at present = 54,000.

||TO FIND||

• Population a year ago.

||SOLUTION||

Let's,

Present Population be x

• $\sf{x = 54000-(8\%\;of\;54000)}$

$54000 - ( \frac{8}{100} \times 54000) \\ 54000 - (8 \times 540) \\ 54000 - 4320 \\ 49680$

Population at Present

• $\longmapsto\;{\bold{49680}}$

$\tt{@MrMonarque}$

Hope It Helps You ✌️